Question

Q) A tower stands vertically if angle of elevatio to top of tower is 60° from distance of 10m than find it's height ?​

Answer 1

Answer:

10$\sqrt{3}$

Step-by-step explanation:

tan60=h/10

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Answer 2

Answer:

Step-by-step explanation:

Let the height of the tower be x.

So AB = x meter

Distance of point from the foot of tower = 10m

Hence, CB = 10m

Angle of elevation = 60°

Angle ACB = 60°

Since tower is vertical to the ground,

Angle ABC = 90°

Now, tanC = Side opposite to angle C/Side adjacent to angle C

         tanC = AB/CB

      tan60° = AB/CB

            √3 = x/10

        10√3 = x

               x = 10√3

Hence, the height of the Tower is 10√3 m

Hope you find it helpful :)