Question

Q. AB is parallel to FG . Angles are shown in the figure. Find x and report the answer as x/ 2.

fig is attached above

please let me know the answer# with explanation
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Answer 1

Answer:

x=130°

Step-by-step explanation:

Let transversal DE ( E is the point where angle x+10 forms) intersects AB & FG at M & N resp.

In ∆EFN, angle ENF = (x+10) - (40) = x - 30

Now, angle ENF = angle DMB = x - 30, as AB || FG.

Now, angle COD ( where O is the point of intersection of DM & CB ) = 180 - [20+(x-30)]=170-x

Now, angle CDE =x = 90+(170-x)=260-x

x = 260-x

x = 130°

hope you get it!

thanks!