Question

Q- ABCD is rectangle in which diagonal AC bisect angle A as well as angle C ,show that ABCD is a square

I just want to know is this correct please help tommorow is my exam​

Answer 1

Step-by-step explanation:

ABCD is a rectangle , in which diagonal AC bisect ∠A as well as ∠C. Therefore,

∠DAC=∠CAB→(1)

∠DCA=∠BCA→(2)

A square is a rectangle when all sides are equal. Now,

AD∥BC & AC is transversal, therefore

∠DAC=∠BCA [Alternate angles]

From (1), ∠CAB=∠BCA→(3)

In △ABC,

∠CAB=∠BCA , therefore

BC=AB →(4)[sides opposite to equal angles]

But BC=AD & AB=DC→(5) [Opposite sides of rectangle]

Therefore from (4)& (5),

AB=BC=CD=AD

Hence, ABCD is a square.