Q:-Add the additive inverse of (-12 + 16 - 42 ÷ 3 of 7) to the product of -2, -3 and -4. Ans it Plzzz
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Hi ,
Additive inverse of ( -12 +16 -42÷3of7)
= ( -12 +16 - ( 42/3 )× 7
= 4 - 14 × 7
= -10 × 7
= -70 ---( 1 )
Product of ( -2 ) ( - 3 ) ( -4 )
= - 24 ----( 2 )
According to the problem given ,
Additive inverse of ( 1 ) + ( -24 )
= 70 - 24
= 46
I hope this helps you.
: )
Additive inverse of ( -12 +16 -42÷3of7)
= ( -12 +16 - ( 42/3 )× 7
= 4 - 14 × 7
= -10 × 7
= -70 ---( 1 )
Product of ( -2 ) ( - 3 ) ( -4 )
= - 24 ----( 2 )
According to the problem given ,
Additive inverse of ( 1 ) + ( -24 )
= 70 - 24
= 46
I hope this helps you.
: )
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