Question

Q
al) Find the circumference of circle where
3.5cm? ( TT= 22)

radius is​

Answer 1

Correct Question:-

• Find the circumference of circle where radius is 3.5cm. Take = $\sf{\pi - \dfrac{22}{7}}$

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Given:-

• Radius (r) = 3.5 cm

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To find:-

• Circumference of circle.

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Solution:-

★Formula used:-

$\star{\boxed{\sf{\orange{Circumference\: of\: circle = 2 \pi r}}}}$

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$\tt\longmapsto{2 \pi r}$

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$\tt\longmapsto{2 \times \dfrac{22}{7} \times 3.5}$

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$\tt\longmapsto{\boxed{\red{22\: cm}}}$

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Hence,

• the circumference of the circle is 22 cm.

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Diagram:-

$\setlength{\unitlength}{1.2mm}\begin{picture}(50,55)\thicklines\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\put(5,30){\line(5,0){40}}\put(25,30){\circle*{1.5}}\put(13,26){\sf\large{d = 7}}\put(25,30){\line(5,6){13}}\put(28,37){\sf\large{r = 3.5}}\put(6,42){\sf\large{C = 22}}\end{picture}$