Question

Q]. An electron moving with a velocity of 5 X 104 ms-1enters into a uniform electric field
and acquires a uniform acceleration of 104 ms-2in the direction of its initial motion.
(i) Calculate the time in which the electron would acquire a velocity double of its
initial velocity.
(ii) How much distance the electron would cover in this time ?

Answer 1

Answer :-

Initial velocity of the electron is u =5×10⁴m/s

Acceleration of the electron is a=10⁴m/s²

From first equation of motion,

v=u+at

2u=u+at

t=u/a=(5×10⁴)/(10⁴)=5s