Q. An engine of a train, moving with uniform acceleration, passes the signal post with velocity u and the last compartment with velocity v. The velocity with which middle point of the train passes the signal post is what?
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Answer:
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Explanation:
(1) length of train :- l
When last compartment passes through pole distance covered by first compartment is l
∴v2=u2+2al
∴a=2lv2−u2
Now, when middle post passes, distance covered by first compartment is 2l
∴vf2=u2+2Ral
=u2+(2lv2−u2)l=2v2+u2
∴vf=2v2+u2
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Hope the answer is correct and helpful.
Explanation:
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(1) length of train :- 1
When last compartment passes through pole distance covered by first compartment is 1
*v2=u2+2al
a=2lv2-u2
Now, when middle post passes, distance covered by first compartment is 21
*vf2=u2+2Ral
=u2+(2lv2-u2)=2v2+u2
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