Physics, asked by Anonymous, 10 hours ago

Q. An engine of a train, moving with uniform acceleration, passes the signal post with velocity u and the last compartment with velocity v. The velocity with which middle point of the train passes the signal post is what?

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Answers

Answered by ankitrock
1

Answer:

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Explanation:

(1) length of train :- l

When last compartment passes through pole distance covered by first compartment is l

∴v2=u2+2al

∴a=2lv2−u2

Now, when middle post passes, distance covered by first compartment is 2l

∴vf2=u2+2Ral

=u2+(2lv2−u2)l=2v2+u2

∴vf=2v2+u2

Answered by shariqrashid123
1

Hope the answer is correct and helpful.

Explanation:

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(1) length of train :- 1

When last compartment passes through pole distance covered by first compartment is 1

*v2=u2+2al

a=2lv2-u2

Now, when middle post passes, distance covered by first compartment is 21

*vf2=u2+2Ral

=u2+(2lv2-u2)=2v2+u2

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