Physics, asked by physicslover666, 10 months ago

Q - An object 2.5 cm long, is placed on the axis of a concave mirror
of 30 cm radius of curvature, at a distance of 10cm from it.
Find the position, size and nature is image formed
[ virtual, erect, 7.5 cm high; V= 300m]\-
Explain this Numerical...​

Answers

Answered by Anonymous
23

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⛄ ʜᴇʀᴇ, ɢɪᴠᴇɴ

★ ʜ = 2.5 ᴄᴍ,

★ ᴜ = -10 ᴄᴍ

ғ = ʀ/2 = -30/2 = -15 ᴄᴍ

1/ғ = 1/ᴜ + 1/ᴠ

ᴛʜᴇʀᴇғᴏʀᴇ,

-1/15 = -1/10 + 1/ᴠ => -1/15 + 1/10 = 1/ᴠ

ᴛʜᴇʀᴇғᴏʀᴇ,

1/ᴠ = -2+3/30 = 1/30

ᴛʜᴇʀᴇғᴏʀᴇ,

ᴠ = 30 ᴄᴍ.

ᴀs ᴠ ɪs +ᴠᴇ, ᴛʜᴇʀᴇғᴏʀᴇ, ᴛʜᴇ ɪᴍᴀɢᴇ ғᴏʀᴍᴇᴅ ɪs ᴠɪʀᴛᴜᴀʟ, ᴇʀᴇᴄᴛ ᴀɴᴅ ᴏɴ ᴛʜᴇ ʙᴀᴄᴋ sɪᴅᴇ ᴏғ ᴛʜᴇ ᴍɪʀʀᴏʀ.

sɪᴢᴇ:- ᴍᴀɢɴɪғɪᴄᴀᴛɪᴏɴ, ᴍ = ʜ'/ʜ = - ᴠ/ᴜ

ʜ' = - ᴠ/ᴜ × ʜ = -30/-10 × 2.5 = + 7.5 ᴄᴍ.

ᴛʜᴇ ɪᴍᴀɢᴇ ɪs ᴠɪʀᴛᴜᴀʟ ᴀɴᴅ ᴍᴀɢɴɪғɪᴇᴅ. ᴛʜᴇ +ᴠᴇ sɪɢɴ ɪɴᴅɪᴄᴀᴛᴇs ᴛʜᴀᴛ ᴛʜᴇ ɪᴍᴀɢᴇ ɪs ғᴏʀᴍᴇᴅ ᴀʙᴏᴠᴇ ᴛʜᴇ ᴘʀɪɴᴄɪᴘᴀʟ ᴀxɪs, ɪ.ᴇ., ɪᴛ ɪs ᴠɪʀᴛᴜᴀʟ ᴀɴᴅ ᴇʀᴇᴄᴛ.

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