Question

Q) An object 4 cm high is placed at a distance of 15 cm in front of a diverging mirror of focal length 10 cm. Graphically find the position, size and nature of an image formed and also show the verification by using mirror equation.

Answer 1

answer + Explanation

Here, h1=4cm,u=−15cm,f=−10cm,v=?

v=?, h2=?

From mirror formula

1v+1u=1f

1v=1f−1u=1−10+115=−130

v=−30cm

∴ Distance of screen from the mirror =30cm

As h2h1=−vu=+30−15=−2

h2=−2h1=−2×4=−8cm

Negative sign is for inverted image.