Question

Q. An object of mass 20kg is raised to a height of 10 m above the ground. What is its potential energy? If the object is allowed to fall, find its kinetic energy when it is half way down.
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Answer 1

$\Large{\underbrace{\underline{\bf{TO\: FIND\::}}}}$

• Potential energy of object.
• Kinetic energy of the object when it is half way down.

$\Large{\underbrace{\underline{\bf{GIVEN\::}}}}$

• Mass of an object is 20 kg.

• The object is raised to a height of 10 m above the ground.

$\Large{\underbrace{\underline{\bf{SOLUTION\::}}}}$

☛ To calculate the potential energy, we use the following formula.

$\orange\bigstar\:{\bf{\pink{P.E\:=\:m\:g\:h}}}\:\green\bigstar$

Where,

m is the mass of the object.

g is the gravitational acceleration = 10 m/s²

h is the height raised by object.

➵ P.E = 20 × 10 × 10

➵ P.E = 2000 Joules

∴ Potential energy of the object is 2000 J.

✰ As we know that when object fall's from a height, then the potential energy of the object is converted into kinetic energy.

☛ Thus when object is at half way then kinetic energy of the object is,

➵ K.E = $\rm{\dfrac{Potential\: energy}{2}}$

➵ K.E = $\rm{\dfrac{2000}{2}}$

➵ K.E = 1000 Joules

• ∴ The kinetic energy of the object when it is half way down is 1000 J.

Answer 2

Explanation:

$\Large{\underbrace{\underline{\bf{TO\: FIND\::}}}}$

Potential energy of object.

Kinetic energy of the object when it is half way down.

$\Large{\underbrace{\underline{\bf{GIVEN\::}}}}$

Mass of an object is 20 kg.

The object is raised to a height of 10 m above the ground.

$\Large{\underbrace{\underline{\bf{SOLUTION\::}}}}$

☛ To calculate the potential energy, we use the following formula.

$\orange\bigstar\:{\bf{\pink{P.E\:=\:m\:g\:h}}}\:\green\bigstar$

Where,

m is the mass of the object.

g is the gravitational acceleration = 10 m/s²

h is the height raised by object.

➵ P.E = 20 × 10 × 10

➵ P.E = 2000 Joules

∴ Potential energy of the object is 2000 J.

✰ As we know that when object fall's from a height, then the potential energy of the object is converted into kinetic energy.

☛ Thus when object is at half way then kinetic energy of the object is,

➵ K.E = $\rm{\dfrac{Potential\: energy}{2}}$

➵ K.E = $\rm{\dfrac{2000}{2}}$

➵ K.E = 1000 Joules

∴ The kinetic energy of the object when it is half way down is 1000 J.