Question

Q.An organic compound has the moleculer formula C5H10O. The compound doesnot reduce Tollen's reagent,but reacts with Brady's reagent to give orange precipitate .On vigorous Oxidation,the molecule produces ethanoic acid and propanoic acid.The compound also gives iodofrom test .Identify the compound and write equations for chemical reactions involved .❤☺_______plz answer this question correctly don't unneccessary answer________✌​

Answer 1

Explanation:

It does not reduce tollen’s reagent then compound should be an aldehyde or ketone.

It forms orange precipitate with 2,4-DNP reagent therefore it should be either aldehyde or ketone.

CH3-CH2C=O-CH2CH3

It does not give yellow precipitate on treatment with NaOH and iodine (iodoform reaction). Then it is not an aldehyde and should not be a methyl ketone and hence it is diethylketone (C5H10O) satisfies molecular formula for.

CH3CH2C(OH)(Ph)CH2CH3

Answer 2

Answer:

• $CH_3COCH_2CH_2CH_3+O_2- >$$CH_3COOH+C_3H_6O_2$

Explanation:

• Tollens' test, also known as a silver-mirror test, is a qualitative test used to differentiate between an aldehyde and a ketone, and it produces positive findings with an aldehyde.
• An organic molecule with the chemical formula $C_5H_{10}O$ that does not reduce Tollen's reagent is not an aldehyde.
• It also produces an orange precipitate when it interacts with Brady's reagent, indicating that it is a ketone.
• The equation-$CH_3COCH_2CH_2CH_3+$$C_6H_6N_4OH_4 - >$$CH_3CH_2CH_2CH_3N_2H - C_6H_4N_2O_4$
• On intense oxidation, the molecule yields ethanoic acid and propanoic acid, with methyl ketone being the sole ketone that gives the iodoform test.
• The formula- $CH_3COCH_2CH_2CH_3+O_2- >$$CH_3COOH+C_3H_6O_2$