Q. An uncharged capacitor having capacitance C is connected across a battery of emf V. Now the battery is disconnected and reconnected across same battery but with reverse polarity, then what is the ratio of total thermal energy produced to the total energy supplied by the battery?
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Explanation:
ΔW=ΔU+ΔH
Work done by battery,
∴W=2CE×E
Change in energy stored in capacitor,
ΔU=0
Thus, Heat dissipated,
ΔH=2CE
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