Question

q
Analysis
367.5 gram KC1O2(M = 122-5) is heated. How many
gram KCl and oxygen is produced.

Answer 1

Answer:

here is ur answer

Explanation:

Balanced chemical equation for heating kclo3 is

2kclo3→2kcl+3o2

Mass mass ratio:

2×122.5gm:     2×74.5gm:    3×32gm

Mass of kclo3/Mass of kcl= 2×122.5/2×74.5 ⇒367.5/W=122.5/74.5

Wkcl=3×74.5=223.5gm

Mass of kclo3/Mass of o2= 2×122.5/3×32⇒ 367.5/W=2×122.5/3×32

Woxygen=144gm

Mass volume analysis

Now again consider decomposition of kclo3

2kclo3→2kcl+3o2

Mass volume ratio

2×122.5gm:  2×74.5gm:   3×22.4 it at STP

we can use to relation for volume and oxygen

Mass of kclo3/volume of o2 at stp=2×122.5/3×22.4It→ans1

Mass of kcl/volume of o2 at stp= 2×74.5/3×22.4It→ ans2