Q. Anita
goes
h
cand
goed to college at 20 km/
vreaches
college 4 minutes late
Wert ctione she
at 25km/wand
reaches the college a minutes eacher
than the sh scheduled time. What
is the dotance
of sot
Cet T be the time actual
20 km/owe min
of her school ?
Answers
Answer:
5 min late
Step-by-step explanation:
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Given :- Anita goes to College at 20 km/h and reaches college 4 minutes late. Next time she goes at 25 km/h and reaches the college 2 minutes earlier than the scheduled time. What is the distance of her school ?
(A) 16 km
(B) 12km
(C) 15km
(D) 10 km
Solution :-
Let us assume that, the distance of her school is x km.
Case 1) :-
→ Time taken to go to school at 20 km/h = D/S = (x/20) hours.
and she reaches 4 minutes late.
so, we can say that,
→ Actual time to reach school = {(x/20) - (4/60)} hours.
Case 2) :-
→ Time taken to go to school at 25 km/h = D/S = (x/25) hours.
and she reaches 2 minutes earlier.
so, we can say that,
→ Actual time to reach school = {(x/25) + (2/60)} hours.
therefore,
→ {(x/20) - (4/60)} = {(x/25) + (2/60)}
→ (x/20) - (x/25) = (2/60) + (4/60)
→ (5x - 4x)/100 = (6/60)
→ (x/100) = (1/10)
→ x = (100/10)
→ x = 10 km/h. (D) (Ans.)
Hence, the distance of her school is 10 km/h .
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