Question

Q) At what temperature will the mass of 198g of carbon-dioxide gas at 2 atmospheric pressure take up a volume of 35L? (Gas constant= 0.0821 L atm. K-mol-)​

Answer 1

Answer:

18.9 Kelvin(k)

Explanation:

since PV=nRT

n(number of moles)=w/m

w means the weight of gas and m means the molecular mass of the gas and CO2 has a molecular mass of 44g.

in 198g of CO2 there will be 4.5 moles

we need to find temperature so

T=PV/nR

Substituting the values we get

T=2atm×35L/4.5mol×0.0821 (L×atm/k×mol)

so we get 18.9 k

hope you understand it