Question

Q. ax²+bx+c =0
Two zeroes of this Equation are
n and m
Then, n²+nm+m²


PLEASE SOLVE THIS​

Answer 1

Answer:

ANSWER

β

α

=

n

m

or by ratio proportion theory,

m

α

=

n

β

=

m+n

α+β

=

(

mn

αβ

)

∴mn(α+β)

2

=αβ(m+n)

2

or mn(−

a

b

)

2

=(m+n)

2

a

c

or mnb

2

=ac(m+n)

2

Answer 2

Answer:

As the two zeroes of the equation ax²+bx+c are n and m

so, n+m = -b/a

nm= c/a

(a/q),

n²+nm+m²= (n+m)²-nm

= (-b/a)²- c/a= b²/a²-c/a

= b²-ac/a²( l.c.m of a and a² is a² )

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