Question

Q- Balance the following eq. in acidic. medium by both oxidation no. and in election methods and identify the oxidant and reductant
Sn + NO3 + Ht SnO₂ + NO + H₂O lo​

Answer 1

Explanation:

Zn+HNO 3

→4Zn(NO 3 )2 +N2O+H 2O

Balance all atoms other than H and O.

4Zn+10HNO 3

→4Zn(NO 3 ) 2 +N2 O+H 2O

The oxidation number of Zn changes from 0 to +2. The change in the oxidation number of one Zn atom is +2. For 4 Zn atoms, the total change in the oxidation number is 8.

The oxidation number of N changes from +5 to +1. The change in the oxidation number of one N atom is 4. For 2 N atoms, the total change in the oxidation number is 8.

The increase in the oxidation number is balanced with a decrease in the oxidation number O atoms are balanced adding 4 water molecules on RHS.

4Zn+10HNO 3

→4Zn(NO 3 )2 +N 2 O+5H 2O

Hydrogen atoms are balanced.

This is the balanced chemical equation.