Math, asked by gavarastar, 4 months ago

Q. Booklet A
Code
30.
The slope of the line y = 2020 is m, and the slope of the line joining the points
(-5, 1) and (3, – 5) is me, and the x- intercept of line 2x – 3y + 5 = 0 is a, then
the value of (m, xm,)
y=2020 అనే సరళరేఖ వాలు m; (-5, 1) మరియు (3, - 5) అనే బిందువులను కలుపు రేఖ వాలు mp;
2x-3y + 5 = 0 రేఖ యొక్క X-అంతరఖండం = a అయితే (m, xma) యొక్క విలువ
-3
-5
(A) 2
(B)
B
(C)
(D)
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4
0​

Answers

Answered by kethavath801
0

Answer:

m=-0/1

me=Y-y/X-x=-5-1/3+5=-6/8=-3/4

a=-5/2

Therefore (M×m)a=(0×-3/4)‐⁵/2=0

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