Question

q box contains 90 discs which are numbered from 1 to 90.if one disc is drawn at random,find the probability that is bears: i) a perfect square ii) a number divisible by 5​

Answer 1

Answer:

Solution(ii):

Let F be the event of drawing a perfect square numbered disc from the box of discs numbered from 1 to 90

Perfect square numbers from 1 to 90=1,4,9,16,25,36,49,64,81

No. of favorable outcomes=9

Total no. of possible outcomes =90

We know that, Probability P(F) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

90

9

=

10

1

Therefore, the probability of drawing a perfect square numbered disc from the box of discs numbered from 1 to 90=

10

1

Solution(iii):

Let G be the event of drawing a disc with a number divisible by 5 from the box of discs numbered from 1 to 90

Numbers divisible by 5 from 1 to 90=5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90

No. of favorable outcomes=18

Total no. of possible outcomes =90

We know that, Probability P(G) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

90

18

=

5

1

Therefore, the probability of drawing a disc with a number divisible by 5 from the box of discs numbered from 1 to 90=

5

1

hope it will help you

Answer 2

Answer:

I don't know answer sorry