Q.-By selling 45 oranges for rs.80, a man loses 20% how many should he sell for rs.48 so as to gain 20% in the transaction?
Answers
Answered by
3
SP=CP(100-L)/100, where L is loss in percent.
This give CP of 45 oranges = (80×100)/(100-20)
= ₹100
To gain 20% he should sail his 45 oranges for SP=CP(100+P)/100
=₹100(100+20)/100
=₹120
Therefore, SP of 48 oranges should be
= ₹(120×48)/45 =₹108 [Answer]
This give CP of 45 oranges = (80×100)/(100-20)
= ₹100
To gain 20% he should sail his 45 oranges for SP=CP(100+P)/100
=₹100(100+20)/100
=₹120
Therefore, SP of 48 oranges should be
= ₹(120×48)/45 =₹108 [Answer]
Similar questions