Question

Q. Calculate percentage of all elements present in the element of glucose . ( In detail )

Answer 1

Percentage composition of a compound is a ratio of an amount of each element to the total amount of individual elements in a compound, which is then multiplied with 100. Let us take an example of H2O i.e. Water. Water has 2 molecules of hydrogen, and one mole of water is of 18.0152 grams. And one mole of a hydrogen atom is of 1.008 grams. So, 2 hydrogen moles weighs 2.016 grams. Hence, one mole of water has 2.016 grams of hydrogen mole. Therefore, the percentage composition of hydrogen would be 2.016/18.0152 = 11.19%. Now let us study in detail about Percentage composition and its formula.

Atomic Mass

Dalton's Atomic Theory

Stoichiometry

What is Percentage Composition?

The percentage composition of a given compound is nothing but the ratio of the amount of each element to the total amount of individual elements present in the compound. We then multiply this value by 100. Here, we measure the quantity in terms of grams of the elements present in the solution.

The percent composition of any compound is an expression of its composition in terms of all the elements present. The significance of this composition calculation is found in the chemical analysis.

The Formula for Percentage Composition

We can express the percentage composition of a given element using the formula below:

Here, % CE is the percentage composition of the element E. This is the value that we are going to calculate. The numerator on the right side indicates the total amount of element E present in the compound. On the other hand, the denominator is an expression for the total amount of all the elements present in the compound.

We multiply this ratio by 100 to get the percentage form of the composition. Let us now look at the mass percentage of composition in more details. We will also look at its importance

Answer 2

FORMULA OF GLUCOSE = C2 H6 O6.

MASS OF WHOLE COMPOUND = 12 *2 + 1*6 +

16* 6 = 24 + 6 + 76 = 106 g.

For % of Carbon, Mass of carbon in C2 H6 O6 = C2 = 12 *2 = 24 g.

% of Carbon = 24 * 100 / 106 = 1200 /53 %

For % of Hydrogen, Mass of H in C2 H6 O6 =

H6 = 1*6 =6 g.

% of H = 6 * 100 / 106 = 300 / 53%

% of Oxygen, Mass of Oxygen in C2 H6 O6 =
O6 = 16 * 6 = 76 g.

% of O = 76 * 100 / 106 = 3800 / 53 %.