Chemistry, asked by nehasidxo19, 2 months ago

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Q) Calculate the heat of formation of M2A at 25°C:
2M + 1/2 A2 → M2A AH =?
M + Y2A ► MAY + 1/2 Y2 AH = -43.2 KJ/mole
Y2 + 1/2 A2 → Y2A.
AH = - 68.5 KJ/mole
M2A + Y2A 2MAY
AH = - 63.2 KJ/mole

Answers

Answered by anant4256kushwaha
0

Answer:

Results for Calculate the heat of formation of M2A at 25°C: 2M + 1/2 A2 → M2A AH =? M + Y2A ► MAY + 1/2 Y2 AH = "-43.2" KJ/mole Y2 + 1/2 A2 → Y2A. AH = - 68.5 KJ/mole M2A + Y2A 2MAY AH = - 63.2 KJ/mole

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