Question

Q. Calculate the internal energy changes of a system when 10 ks of work is done on the system and 2 kJ heat is given out by the system ​

Answer 1

Answer:

(i) Here, q = +15 kJ

w = – 5 kJ

∴ According to first law of thermodynamic

ΔU = q + w = 15 + (–5) = 10 kJ

Thus, internal energy of the system increases by 10 kJ

(ii) Here, w = + 5 kJ

q = – 5 kJ

∴ According to first law of thermodynamics,

ΔU = q + w = – 15 + (+ 5) = – 10 kJ

Thus, the internal energy of the system decreases by 10 kJ.

Explanation:

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