Question

Q. Calculate the
magnitude of electrostatic force
between a proton and an electron separated by
distance of 0.5 A ( 1 A = 10^-10m). given that
magnitude of charge of proton and electron do be
1.6 x 10-19c and 1/4Π€= 9 X 10^9 Nm^2C^2​

Answer 1

Explanation:

Electrostatic Force = Kq1q2 / r^2

Kq1q2 = (9 x 10^9) x (1.6 x 10^-19) x (1.6 x 10^-19)

= 23.04 x 10^-29

r^2 = (0.5 x 10^-10)^2 = 0 .25 x 10^-20

Kq1q2 / r^2 = 23.04 x 10^-29 / 0 .25 x 10^-20

= 92.16 x 10^-9 = (9.216 x 10^-10) N

Answer 2

Electrostatic Force = 9.216 * 10^-10 N

Explanation:

Charge on proton = a = 1.6 * 10^-19 C

So charge on electron q = 1.6 * 10^-19 C

Distance between charges r = 0.5 * 10^-10 m

k = 9 * 10^9 Nm²C²

So  Electrostatic Force = kq² / r²

 = 9 * 10^9 * 1.6 * 1.6 * 10^-38 / 0.25 * 10^-20

 = 92.16 * 10^-9

 = 9.216 * 10^-10 N