Q) Calculate the mole fraction of glucose and water in 6% (by mass ) solution
Answers
Answer:
Mole Fraction=
Moles of solute+Moles of solvent
Moles of solute
Moles of glucose (solute)=
180
45
=0.25 (Since molecular mass of C
6
H
12
O
6
i.e glucose is 180 g)
Moles of solvent=
18
45
=2.5 (Since molecular mass of H
2
O i.e water is 18 g)
Mole fraction=
0.25+2.5
0.25
=0.0909=
11
1
Now, for mole fraction of NaOH, let us take weight of NaOH to be dissolved =x g
So, Moles of NaOH=
40
x
[Since, molecular weight of NaOH is 40 g]
And Moles of H
2
O=
18
90
Mole fraction=
40
x
+
18
90
x/40
0.0909=
40
x
+
18
90
x/40
Therefore, x=20 g
Explanation:
Answer:
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