Question

Q.Calculate the mole fraction of Hcl in a solution containing 24.8% of Hcl by mass.​

Answer 1

Answer:

Given: the solution contains 24.8% of HCl by mass.

100 g of solution, 24.8 g of HCl is present.

Mole fraction of HCl=No. of moles of HCl+No. of moles of waterNo. of moles of HCl

=36.524.8+1875.236.524.8

=0.68+4.210.68=4.890.68=0.139

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