Question

Q.Calculate the mole fraction of sodium chloride Nacl in a solution 5 g of Nacl dissolved in 1000 g of H2O.​

Answer 1

$\huge \underline \pink{Answer:}$

Explanation:

$\red{\text{Given:}}$

➡ of solute (Nacl) = 5g

➡Mass of solution = 1000g

$\purple{Solution:}$

➡nNacl = 5/58.5 = 0.085

➡nH2O = 1000/18 = 55.55

xHcl = nNacl/ nNacl + nH2O

= 0.0855/0.0855 + 55.5

= 0.0855/55.585

= 85.5 × 10^-3/55.58

= 1.538 × 10^-3

= 0.001538

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Answer 2

$\Huge{\red{\underline{\textsf{Answer}}}}$

Mass of solution = 1000g

nNacl = 5/58.5 = 0.085

nH2O = 1000/18 = 55.55

xHcl = nNacl/ nNacl + nH2O

= 0.0855/0.0855 + 55.5

= 0.0855/55.585

= 85.5 × 10^-3/55.58

= 1.538 × 10^-3

= 0.001538