Question

Q. Calculate the number of atoms of
hydrogen present in 5.6 g of urea, ,
(NH),CO. Also calculate the number
of atoms of N, C and O.
(Ans. : No. of atoms of H = 2.24 x 1023,
N=1.124 x 1023 and C = 0.562 x 1023, O
= 0.562 x 1023)
please give simple word answer​

Answer 1

Answer:

Thus, 5.6 g of urea contains 2.247×1023 atoms of hydrogen.

Explanation:

The number 6.022×1023 is known as Avogadro's number. Thus, the numberof moles of urea present in 5.6 g ofurea are 0.0933 mol. Thus, 0.0933 molurea contains 0.3732 mol of hydrogen. Thus, 5.6 g of urea contains 2.247×1023 atoms of hydrogen.

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