Question

Q. Calculate the retardation
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Answer 1

Answer:

It's very simple to find the formula for (a+b+c+d)^2.

Consider (a+b) be ‘x’ and(c+d) be ‘y’.

Then the above problem'll resolve as-

(x+y)^2

Now, apply the formula for (a+b)^2-

x^2 + y^2 + 2xy.

Now put the values of ‘x’ ( a+b) & ‘y’ (c+d)

(a+b)^2 + (c+d)^2 + 2 (a+b)(c+d)

Now, again apply the formula of (a+b)^2-

a^2 +b^2 + 2ab + c^2 + d^2 + 2cd + 2 (a+b)(c+d).

So, the formula for (a+b+c+d)^2 is-

a^2 + b^2 + 2ab + c^2 + d^2 + 2cd + 2(a+b)(c+d).

Answer 2

Explanation:-

Acceleration=Final velocity-Initial Velocity/times

So the retardation starts from 5th second and end at 10th second

So let's calculate retardation:-

Final velocity=0

initial velocity=10 m/s

Time=5

Acceleration=0-10/5

Acceleration=-10/5

Acceleration=-2 m/s²

So the acceleration is -2 m/s² and retardation is 2 m/s²