Question

Q.
Calculate the volume of 24 x 10^25 molecules of Carbon dioxide at STP.​

Answer 1

Answer:

Number of moles of CO2 (n) = (24 × 10²⁵)÷(6 × 10²³)

n = 400 moles.

1 mole → 22.4 L (STP)

400 moles → 22.4 × 400 L

So, the volume is 8960 L.

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