Question

Q) Combustion of glucose takes place according to the equation,
C6H1206 +602-→ 6CO2 + 6H20;
AH = -72 kcal
How much energy will be required for the production of 1.6 g of glucose? (Molecular mass of
[AFMC 1999; MPPMT 2005]
(b) 0.64 kcal
(c) 6.4 kcal
(d) 64 kcal
glucose = 180 g)
(a) 0.064 kcal​

Answer 1

Answer:

0.64 kcal

Explanation:

molar mass of C6H12O6=180 g mol-1

180g of glucose require energy =72 kcal

1.6g of glucose require energy =72*1.6/180

=0.64 kcal

hence, option (b) is correct.

Answer 2

Explanation:

Option b is correct answer mate :)