Question

Q. Consider the following reactions:
(i) H(aq) + OH (diq) = H2O(1),
AH = -x, kJ mol!
(ii) H2(g) + 1/2O2(g) = H2O(),
AH = -X2 kJ mol!
(iii) CO2(g) + H2(g) = CO(g) + H2O(1)
AH = -Xz kJ mol
(iv) CH2(g) + 5/202(g) = 2C02(g) + H2O(1)
AH = +X4 kJ mol!
Enthalpy of formation of H2O() is
(a) +X3 kJ mol (b) X4 kJ mol!
(c) +XkJ mol (d) -X2 kJ mol!!
.

Answer plz... ​

Answer 1

Answer:

H

+

(aq)+OH

−

(aq)=H

2

O(l);ΔH=−X

1

kJ.mol

−1

II) H

2

(g)+

2

1

O

2

(g)=H

2

O(l);ΔH=−X

2

kJ.mol

−1

III) CO

2

(g)+H

2

(g)=CO(g)+H

2

O(l);ΔH=+X

3

kJ.mol

−1

IV) C

2

H

2

(g)+

2

5

O

2

(g)=2CO(g)+H

2

O(l);ΔH=+X

4

kJ.mol

−1