Question

Q.Construct a triangle PQR such that PQ=5cm LP=90° and QR=8cm​

Answer 1

Thanks for free points

Answer 2

Step-by-step explanation:

1. Draw a line segment QR of length 3cm.

2. Now, we draw 95

o

degrees from point Q.

3. Taking Q as centre, 5cm radius, we draw an arc. Let the point where arc intersects the ray be point p.

4. Joint PR and label the sides.

Thus, PQR is the required triangle.

Hope it's Helpful!!!

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