Question

Q coulomb of point charge is placed at the center of a spherical shell of radius R. Find the electric flux of through an area 4π(in SI unit) on the shell surface.​

Answer 1

Answer:

From Gauss law,

       ϕ=ε0Qinc

For a spherical shell

→  flux through an area of 4πr2

m2=ε0Q

→  Flux through 1 m2 area =4πR2ε0Q

Also flux through 4πm2=4πR2ε04πQ=R2ε0Q

∴  we can conclude that flux through an area of 4πm2 on a shell is given by =R2ε0Q

Explanation:

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