Question

Q coulomb of point charge is placed at the center of a spherical shell of radius R. Find the electric flux of through an area 4π(in SI unit) on the shell surface.​

Answer 1

Answer:

•From Gauss law,

ϕ=

ε

0

Q

inc

For a spherical shell

→ flux through an area of 4πr

2

m

2

=

ε

0

Q

→ Flux through 1 m

2

area =

4πR

2

ε

0

Q

Also flux through 4πm

2

=

4πR

2

ε

0

4πQ

=

R

2

ε

0

Q

∴ we can conclude that flux through an area of 4πm

2

on a shell is given by =

R

2

ε

0

Q

∴ Option (A) is the correct answer.

Explanation:

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