Question

Q. Deduce the expression for the equivalent resistance of the parallel combination of three resistors R1,R2 and R3. Consider the following electric circuit:

(i) Which two resistors are connected in series?
(ii) Which two resistors are connected in parallel?
(iii) If every resistor of the circuit is of 2 ohm. what current will flow in the circuit?

Answer 1

a. In parallel combination of resistor

The voltage difference is same across the every resistor.

Let, circuit have voltage difference V then,

b. In parralle combination current is different in each resistor who connected by battery parllely.

c.Assume curcuit current is I then in every resistor have its seperate cuurent by battery is I1,I2,I3.

d. By ohm' s law

I = I1 + I2+ I3

= V/R1 + V/R2 + V/R3

= V(1/R1 +1/R2 +1/R3)

V/R = V(1/R1+1/R2+1/R3)

1/R = 1/R1+1/R2+1/R3

e.It is the total resistor formula who connected in parallel

SERIES COMBINATION:-

a.In series all resistor have same current and different potential drop

across it.

b.let circuit have volatage difference V ,and circuit current I and resistor have its volatge drop as like V1,V2.

c .we use ohm's law

V = V1+V2

IR= IR1 +IR2

( Current is same so we cancel out it)

R=R1+R2

#.It is the total resitance formula for series combination.

#.If all resistor have its value 2 ohm

Then,

Series:

Total resistance = 2+2+2

= 6 ohm

Let ,volatage difference is V

Then current flow is= V/6

Parallel :

Total resistance= 1/2+1/2+1/2

= 3/2

Let we have volatage difference is V

Current flow is= V/(3/2).

Answer 2

Answer:

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Explanation: