Chemistry, asked by student8961, 9 days ago

Q. Describe what happens when hydoxide gas is passed over hot lead oxide?​

Answers

Answered by sonumandi369
0

Answer:

2Pb3O4→6PbO+O2

Explanation:

There are two oxides for lead. One is lead(II) oxide, another one is lead (IV) oxide.

Lead (IV) oxide is thermally unstable and it tends to decompose into lead(II) oxide and oxygen upon heating.

2PbO2→2PbO+O2

Whereas when lead(II) oxide is heated to around 450-480 °C, it forms lead(II,IV) oxide, also known as red lead or triplumbic tetroxide.

6PbO+O2→2Pb3O4

If it is heated above 480 °C, reverse reaction will occur.

2Pb3O4→6PbO+O2

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