Question

Q. Differentiate tan(log (sinx)) with respect to x.
Soln. :​

Answer 1

Answer:

I guess it is correct

Step-by-step explanation:

let y=tan(log(sin x))

dy/dx=sec²(log(sin x)).( 1/sin x)cos x

dy/dx=sec²(log(sin x) ).cot x

Answer 2

Concept :

The study of correlations between triangles' side angles and lengths is known as trigonometry. The field was created in the Hellenistic era in the third century BC as a result of the use of geometry in astronomical research. Students with strong trigonometry skills can calculate complicated angles and dimensions quickly. Among the most useful subfields of mathematics is trigonometry, which is widely used in engineering, architecture, and many other areas.

Given:

$tan(log (sinx))$

Find:

Differentiate $tan(log (sinx))$ with respect to $x.$

Solution:

According to the problem,

$let y=tan(log(sin x))\\dy/dx=sec²(log(sin x)).( 1/sin x)cos x\\dy/dx=sec²(log(sin x) ).cot x$

Hence the answer is $sec²(log(sin x) ).cot x$

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