Q:- Discuss the feasibility of the formation of an ionic bond if --
1) ionization energy of electropositive atom is high and electron affinity of electronegative atom is low.
2) ionization energy of electropositive atom is low and electron affinity of electronegative atom is high.
3) both the atoms are of equal electronegativities.
Answers
Answer:
The feasibility of the formation of an ionic bond depends upon the electronegativity difference between the two atoms taking part in bonding. Only the atoms with high electronegativity difference make ionic bond. In other words formation of an ionic bond depends upon the tendency of electropositive atom to lose an electron and the tendency of electronegative atom to gain an electron.
Explanation:
Lets discuss about the given cases
case 1)
If the ionization energy of electropositive atom is high that means it does not lose an electron easily and in the second electronegative atom the electron affinity is low which means it has less tendency to gain an electron. So both the atoms are not favoring the formation of an ionic bond.
case 2)
If the ionization energy of electropositive atom is low that means it can readily lose an electron and similarly the high electron affinity of electronegative atom favor the atom to gain an electron easily. So in this case the feasibility of formation of an ionic bond is very high.
case 3)
If the electronegativity of both the atoms is same then the electronegativity difference between them is zero and the ability of both the atom to attract or lose the electron is same and hence no transfer of electron takes place and there is no chance of formation of ionic bond.
Answer:
The feasibility of the formation of an ionic bond depends upon the electronegativity difference between the two atoms taking part in bonding. Only the atoms with high electronegativity difference make ionic bond. In other words formation of an ionic bond depends upon the tendency of electropositive atom to lose an electron and the tendency of electronegative atom to gain an electron.
Explanation:
Lets discuss about the given cases
case 1)
If the ionization energy of electropositive atom is high that means it does not lose an electron easily and in the second electronegative atom the electron affinity is low which means it has less tendency to gain an electron. So both the atoms are not favoring the formation of an ionic bond.
case 2)
If the ionization energy of electropositive atom is low that means it can readily lose an electron and similarly the high electron affinity of electronegative atom favor the atom to gain an electron easily. So in this case the feasibility of formation of an ionic bond is very high.
case 3)
If the electronegativity of both the atoms is same then the electronegativity difference between them is zero and the ability of both the atom to attract or lose the electron is same and hence no transfer of electron takes place and there is no chance of formation of ionic bond.