Question

Q. During a camping trip, a group went one -third of the total distance by boat, 10km by foot and One – sixth of it by riding horses. Find the total distance of the trip. Pls ans this question and I will surely mark the first ans as the brainliest ans..

Answer 1

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Q. During a camping trip, a group went 1 - third of the total distance by boat, 10 km by foot and 1 - 6th of it by riding horses. find the total distance of the trip ?

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• let d be the total distance.

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$d = \frac{1}{3} d \: + 10 \: + \frac{1}{6} d$

$\frac{6}{6} d = \frac{2}{6} d \: + \frac{60}{6} + \frac{1}{6} d$

$6d = 2d \: + 60 \: + d$

$6d \: = \: 3d \: + 60$

$3d \: = 60$

$d \: = \frac{60}{3} = 20$

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• therefore total distance = 20

$\large\mathtt\green{Hope\:it\:help}$$<font color = blue >$

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THANKS

Answer 2

✪ Question:

☞ During a camping trip, a group went one -third of the total distance by boat, 10km by foot and One-sixth of it by riding horses. Find the total distance of the trip.

To Find:

☯ The total distance of the trip.

✪ Given:

✧Distance traveled by the group with different medium :-

✧Let the total distance be x .

• Distance Covered by Boat = 10km

• Distance covered by Boat = $\sf{\dfrac{1}{3}x}$

• Distance covered by riding horses = $\sf{\dfrac{1}{6}x}$

✪ Concept:

✧ By solving the equation linearly ,we can find the total distance of the trip.

✪ ATQ:

Total distance = distance traveled by boat + Distance covered By foot + distance traveled by riding horses.

${\boxed{\mathtt{\dfrac{1}{3}x + 10 + \dfrac{1}{6}x} = x}}$

✪ Solution:

Given Equation:

$\sf{\dfrac{1}{3}x + 10 + \dfrac{1}{6}x = x}$

By solving it, we get:-

$\sf{\Rightarrow \dfrac{2x + 60 + 2}{6} = x}$

$\sf{\Rightarrow \dfrac{2x + 61}{6} = x}$

$\sf{\Rightarrow 2x + 61 = x \times 6}$

$\sf{\Rightarrow 3x + 60 = 6x}$

$\sf{\Rightarrow 3x + 60 = 6x}$

$\sf{\Rightarrow 60 = 6x - 3x}$

$\sf{\Rightarrow 60 = 3x}$

$\sf{\Rightarrow \dfrac{\cancel{60}}{\cancel{3}} = x}$

$\sf{\Rightarrow 20\:km = x}$

Hence , the total distance covered is 20 km.

Verification:

Given equation :

$\sf{\dfrac{1}{3}x + 10 + \dfrac{1}{6}x = x}$

Putting the value in the equation..

$\sf{\Rightarrow \dfrac{2 \times 20 + 60 + 20}{6} = 20}$

$\sf{\Rightarrow \dfrac{40 + 60 + 20}{6} = 20}$

$\sf{\Rightarrow \dfrac{120}{6} = 20}$

$\sf{\Rightarrow \dfrac{\cancel{120}}{\cancel{6}} = 20}$

$\sf{\Rightarrow 20 = 20}$

$\boxed{Verified : \because RHS = LHS}$

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