Question

Q.) equation of normal line to y2 =4ax at (a,-2a)
OA) x-y= 3a
OB) x+y+a=0
OC) x+y+3a=0
OD) x+y=0​

Answer 1

Answer:

c I think is the answer sorry if it's wrong it's emergency to give any point sorry once again

Answer 2

Step-by-step explanation:

We have,

${y}^{2} = 4ax$

$\implies 2y \frac{dy}{dx} = 4a$

$\implies \frac{dy}{dx} = \frac{4a}{2y}$

$\implies \frac{dy}{dx} = \frac{2a}{y}$

$\implies \frac{dy}{dx} \bigg| _{ (a , - 2a ) } = \frac{2a}{ - 2a} = - 1$

Equation of normal:

$(y + 2a) (-1 ) + (x - a) = 0$

$\implies \: - y - 2a + x - a = 0$

$\implies \: x - y - 3a= 0$