Math, asked by pragya1565, 10 months ago

【Q】 equilateral ∆ABD and ∆ACE are drawn on the sides of a ∆ABC. Prove that
CD = BE.

Answers

Answered by shruthishirgaonkar

4

Answer:

in abc and ace

ab=ac

bd=ce

angle a is coomn

abc congrueny to ace

b/d=c/e

b×c=c×e

bc=ce

hence proved

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