Q.evaluate each of the following by using identities. a)103 X 107 and b) 95 X 96
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Answered by
4
A) 103×107
(100 + 3) × (100+7)
USING (X+A)(X+B)=X^2+(A+B)X+ AB
=(100^2+(100+3)100+3×100)×(100^2+(100+7)100+100×7
=(10000+10300+300)×(10000+10700+700)
=20600×21400
=440,840,000
B)95×96
=(90+5)(90+6)
USING THE SAME IDENTITY,
=(90^2+(5+90)90+5×90)(90^2+(6+90)90+90×6)
=17,100×17,280
=295,488,000
plz mark it as brainlist
(100 + 3) × (100+7)
USING (X+A)(X+B)=X^2+(A+B)X+ AB
=(100^2+(100+3)100+3×100)×(100^2+(100+7)100+100×7
=(10000+10300+300)×(10000+10700+700)
=20600×21400
=440,840,000
B)95×96
=(90+5)(90+6)
USING THE SAME IDENTITY,
=(90^2+(5+90)90+5×90)(90^2+(6+90)90+90×6)
=17,100×17,280
=295,488,000
plz mark it as brainlist
ankitgupta82:
thax
Answered by
5
♡☆{STEP WISE ANSWER}♡☆
= { 103×107 }
=《100+3》× 《100+7》
=(x+a)(x+b)= x square ( a+b )x +ab
={100 square +{3+7} [100] + [7×3]
=《1000+1000+21》
= (11021)
I hope helpful for you.
Mark as Brainlist
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