Question

Q. evaluate the following x³+y²+z when x = -1,y=2 and z=3
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Answer 1

Answer:

SOLUTION

Since x + y + z = 10

Squaring both sides we get x2 + y2 + z2 + 2(xy + yz + zx) = 100

x2 + y2 + z2 + 2 × 25 = 100

x2 + y2 + z2 = 50

We know that x3 + y3 +z3 – 3xyz = (x+y+z)( x2 + y2 + z2 – xy – yz – zx)

x3 + y3 + z3 – 3 × 100 = (10)(50 – 25)

x3 + y3 +z3 = 250 + 300 = 550

Answer 2

Answer:

6

Step-by-step explanation:

(-1)^3+(2)^2+3

-1+4+3

-1+7

6

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