Q] Explain every step of the answer
Q} A body of mass m is projected horizontally with a velocity v from the top of a tower of height h an it reaches the ground at a distance x from the foot of the tower. If a second body of mass 2 m is projected horizontally from the top of a tower of height 2 h, it reaches the ground at a distance 2 x from the foot of the tower. The horizontal velocity of the second body is:
( answer should come √2v )
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x = v * √(2h/g) [as time of flight = √(2h/g)]
2 x = V * √(2*2h/g)
= V * 2√(h/g) [as time of flight = √(2*2h/g)]
x = V * √((h/g)
Compare two equations with v and V, V = √2 v
2 x = V * √(2*2h/g)
= V * 2√(h/g) [as time of flight = √(2*2h/g)]
x = V * √((h/g)
Compare two equations with v and V, V = √2 v
joshinrexy22:
if it was useful please mark as best
i want every step
i have given the steps
but how to compare please show that
compare the equation va and V
sorry v and V
show in answer edit it
i understood but i am confused to whom i should give the best answer you or kvnmurty
thanks a lot
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