Question

Q:-factorise and hence find roots
${x}^{2} + {(x + 1) }^{2} = 365$
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Answer 1

Answer:

x²+(x+1)²=365

x²+x²+2x+1-365=0

2x²+2x-364= 0

x²+x-182 = 0

it's root x= -1,-182

this is your answer ✔️

Answer 2

factorise and hence find roots

${x}^{2} += 365$

x²+ {(x + 1) }²=365

x²+x²+1+2x=365

2x²+1+2x=365

x=-182,-1