Math, asked by Anonymous, 7 months ago

Q:-factorise and hence find roots
 {x}^{2} + {(x + 1) }^{2} = 365.............._________​

Answers

Answered by Anonymous
7

Step-by-step explanation:

\red{\bold{\underline{\underline{QUESTION:-}}}}

Q:-factorise and hence find roots

 {x}^{2} + {(x + 1) }^{2} = 365

\huge\tt\underline\blue{Answer }

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⟹ {x}^{2}  +  {(x + 1)}^{2}  = 365

⟹ {x}^{2}  +  {x}^{2}  + 2x + 1 = 365

⟹2 {x}^{2}  + 2x - 364 = 0

⟹ {x}^{2}  + x - 182 = 0

⟹ {x}^{2}  + 14x - 13x - 182 = 0

⟹x(x + 14) - 13(x + 14) = 0

⟹(x + 14)(x - 13) = 0

⟹x  + 14 = 0

⟹x - 13 = 0

⟹x =  - 14

⟹x = 13

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answered by ᎷíssGℓαмσƦσυs
1

Answer:

tex] {x}^{2} + {(x + 1) }^{2} = 365.............._________[/tex]

x²+x²+2x+1=365

2x²+2x-364= 0

x²+x-182= 0

root = -1,-184

this is your answer ✔️✔️

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