Question

Q. Factorise using identity:
(i)
36{a}^{2} - 84ab + 49{b}^{2}
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Answer 1

It is in the form
a^2+b^2+2ab=(a-b)^2
36a^2+49b^2-84ab
=(6a-7b)^2
Hope it helped u

Answer 2

Heya! ! .
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$36a {}^{2} - 84ab + 49b {}^{2} \\ = we \: can \: write \: this \: like \: \\ = (6a) {}^{2} - 84ab + (7b) {}^{2} \\ =the \: identity \: used \: here \: is \: \\ = (x - y) {}^{2} = x {}^{2} - 2xy + y {}^{2} \\ so. \\ = (6a) {}^{2} - 2 \times 6a \times 7b - (7b) {}^{2} \\ = (6a - 7b) {}^{2} \\ \\ factors \: are \: . = (6a - 7b)(6a - 7b)$