Question

Q. FIND DY/DX
if y = sin(cosx) PLZ ANSWER MEE JUST

Answer 1

Step-by-step explanation:

let y1=(sinx)cosx

taking log on both sides

logy1=cosxlogsinx

diff. w.r. to x

1/y1.dy1/dx=cosx.(1/sinx).cosx+logsinx.(-sinx)

dy1/dx=(sinx)cosx[cos2x- sin2x.logsinx]/sinx

lety2=(cosx)sinx

taking log on both sides

logy2=sinxlogcosx

diff.w.r.to x

(1/y2)dy2/dx=sinx.(1/cosx)(-sinx)+logcosx .cosx

dy2/dx=(cosx)sinx[-sin2x+cos2x. logcosx]/cosx

dy/dx= sinx)cosx[cos2x- sin2x.logsinx]/sinx

+=(cosx)sinx[- sin2x+cos2x. logcosx]/cosx

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

Answer 2

Answer:

- sinx. cos(cosx)

Step-by-step explanation:

dy/dx = cos(cosx).(-sinx)

= - sinx. cos(cosx)