Question

Q)Find p(0),p(1) and p(-2) for the following polynomial.

i) p(x)= 10x- 4x²-3
ii) p(y)= (y+2)(y-2)​

Answer 1

$\huge\bold{Question:-}$

Find p(0) , p(1) and p(-2) for the following polynomials

i) p(x)= 10x- 4x²-3

ii) p(y)= (y+2)(y-2)

$\huge\bold{Solution:-}$

1)Given,

$p(x) = 10x - 4 {x}^{2} - 3$

$p(0) = 10(0) - 4( {0}^{2} ) - 3$

$= > 0 - 0 - 3 = - 3$

$p(0) = - 3$

-----------------

$p(1) = 10(1) - 4( {1})^{2} - 3$

$= > 10 - 4 - 3 = 3$

$p(1) = 3$

-----------------

$p( - 2) = 10( - 2) - 4( { - 2})^{2} - 3$

$= > - 20 - 16 - 3 = 1$

$p( - 2) = 1$

2)Given,

$p(y) = (y + 2)(y - 2)$

$p(0) = (0 + 2)(0 - 2)$

$= > 2( - 2) = - 4$

$p(0) = - 4$

------------------

$p(1) = (1 + 2)(1 - 2)$

$(3)( - 1) = - 3$

$p(1) = - 3$

-------------------

$p( - 2) = ( - 2 + 2)( - 2 - 2)$

$= > (0)( - 4) = 0$

$p( - 2) = 0$

Hope this is helpful $\huge\bold{✓}$

Answer 2

Hope it helps :)

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